Using Equations To Solve Word Problems

Using Equations To Solve Word Problems-18
This may be for Two Persons, More Than Two Persons or Pipes Filling up a Tank For more Algebra Word Problems and Algebra techniques, go to our Have a look at the following videos for some introduction of how to solve algebra problems: Example: Angela sold eight more new cars this year than Carmen.

This may be for Two Persons, More Than Two Persons or Pipes Filling up a Tank For more Algebra Word Problems and Algebra techniques, go to our Have a look at the following videos for some introduction of how to solve algebra problems: Example: Angela sold eight more new cars this year than Carmen.If together they sold a total of 88 cars, how many cars did each of them sell?

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The equations are generally stated in words and it is for this reason we refer to these problems as word problems. If the two parts are in the ratio 5 : 3, find the number and the two parts.

With the help of equations in one variable, we have already practiced equations to solve some real life problems. Solution: Let one part of the number be x Then the other part of the number = x 10The ratio of the two numbers is 5 : 3Therefore, (x 10)/x = 5/3⇒ 3(x 10) = 5x ⇒ 3x 30 = 5x⇒ 30 = 5x - 3x⇒ 30 = 2x ⇒ x = 30/2 ⇒ x = 15Therefore, x 10 = 15 10 = 25Therefore, the number = 25 15 = 40 The two parts are 15 and 25. Then Robert’s father’s age = 4x After 5 years, Robert’s age = x 5Father’s age = 4x 5According to the question, 4x 5 = 3(x 5) ⇒ 4x 5 = 3x 15 ⇒ 4x - 3x = 15 - 5 ⇒ x = 10⇒ 4x = 4 × 10 = 40 Robert’s present age is 10 years and that of his father’s age = 40 years.

This include geometry word problems Involving Perimeters, Involving Areas and Involving Angles Integer Problems involve numerical representations of word problems.

The integer word problems may Involve 2 Unknowns or may Involve More Than 2 Unknowns Interest Problems involve calculations of simple interest.

Worked-out word problems on linear equations with solutions explained step-by-step in different types of examples. Solution: Then the other number = x 9Let the number be x. Therefore, x 4 = 2(x - 5 4) ⇒ x 4 = 2(x - 1) ⇒ x 4 = 2x - 2⇒ x 4 = 2x - 2⇒ x - 2x = -2 - 4⇒ -x = -6⇒ x = 6Therefore, Aaron’s present age = x - 5 = 6 - 5 = 1Therefore, present age of Ron = 6 years and present age of Aaron = 1 year.5. Then the other multiple of 5 will be x 5 and their sum = 55Therefore, x x 5 = 55⇒ 2x 5 = 55⇒ 2x = 55 - 5⇒ 2x = 50⇒ x = 50/2 ⇒ x = 25 Therefore, the multiples of 5, i.e., x 5 = 25 5 = 30Therefore, the two consecutive multiples of 5 whose sum is 55 are 25 and 30. The difference in the measures of two complementary angles is 12°. ⇒ 3x/5 - x/2 = 4⇒ (6x - 5x)/10 = 4⇒ x/10 = 4⇒ x = 40The required number is 40.

There are several problems which involve relations among known and unknown numbers and can be put in the form of equations. Sum of two numbers = 25According to question, x x 9 = 25⇒ 2x 9 = 25⇒ 2x = 25 - 9 (transposing 9 to the R. S changes to -9) ⇒ 2x = 16⇒ 2x/2 = 16/2 (divide by 2 on both the sides) ⇒ x = 8Therefore, x 9 = 8 9 = 17Therefore, the two numbers are 8 and 17.2. A number is divided into two parts, such that one part is 10 more than the other. Try to follow the methods of solving word problems on linear equations and then observe the detailed instruction on the application of equations to solve the problems.Having difficulty turning a word problem into an algebra equation? With this tutorial, you'll learn how to break down word problems and translate them into mathematical equations.Knowing the mathematical meaning of words allows you to decipher word problems and gives you the power to write your own word problems, too!Ratio Problems require you to relate quantities of different items in certain known ratios, or work out the ratios given certain quantities.This could be Two-Term Ratios or Three-Term Ratios Symbol Problems Variation Word Problems may consist of Direct Variation Problems, Inverse Variation Problems or Joint Variation Problems Work Problems involve different people doing work together at different rates.They may involve a single person, comparing his/her age in the past, present or future.They may also compare the ages involving more than one person.This involve Adding to a Solution, Removing from a Solution, Replacing a Solution,or Mixing Items of Different Values Motion Word Problems are word problems that uses the distance, rate and time formula.You may be asked to find the Value of a Particular Term or the Pattern of a Sequence Proportion Problems involve proportional and inversely proportional relationships of various quantities.Coin Problems deal with items with denominated values.Similar word problems are Stamp Problems and Ticket Problems.

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